4p^2=296

Solution for 4p^2=296 equation:

4p^2=296

We move all terms to the left:

4p^2-(296)=0

a = 4; b = 0; c = -296;
Δ = b2-4ac
Δ = 02-4·4·(-296)
Δ = 4736
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4736}=\sqrt{64*74}=\sqrt{64}*\sqrt{74}=8\sqrt{74}$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{74}}{2*4}=\frac{0-8\sqrt{74}}{8}
=-\frac{8\sqrt{74}}{8}
=-\sqrt{74}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{74}}{2*4}=\frac{0+8\sqrt{74}}{8}
=\frac{8\sqrt{74}}{8}
=\sqrt{74}
$